The solubility of potassium chloride is 34.2 g/100 g h2o at 20°c. a 68.4-g sample of potassium chloride is added to 200.0 g of water at 20°c. is the solution saturated, unsaturated, or supersaturated?

g KCl / g H2O = 68.4 g / 200 g = 0.342 g KCl / g H2O Therefore, the solution is saturated. Hope this answers the question.

The solution is saturated. Explanation: We are given: Solubility of KCl at 20°C = 34.2 g/100 g We need to find the type of solution when 68.4 grams of KCl is added to 200 grams of water at 20°C. There are three possibilities: If concentration is equal to the solubility; it is considered as saturated solution.If concentration is less than the solubility; it is considered as unsaturated solution.If concentration is greater than the solubility; it is considered as supersaturated solution. Ratio of the solubility of two solution is: When 34.2 gram of KCl is dissolved in 100 grams, the ratio becomes: When 68.4 gram of KCl is dissolved in 200 grams, the ratio becomes: As, the ratio of the solubility of both the solutions is equal, which means that the solution is saturated.

The concentration is equal to solubility, so the solution is saturated